What Happens When You Mix Hypochlorous Acid (HClO) And
Hypochlorous acid, HOCl, reacts with water as shown below: HOCl(aq) + H2O(l) <---> OCl-(aq) + H3O+(aq) What is the pH of a 0.033 M aqeous . This is a weak acid at LOW concentration, whose dissociation we probably have to solve analytically We address the equation HOCl(aq) +H_2O(l)rightleftharpoonsH_3O^+ +""^(-)OCl. where K_a=0.011=([H_3O^+][""^(-)OCl])/([HOCl]) And if x*mol*L^-1 dissociates 0.011=x^2/(0.033-x) And so x^2=0.011xx(0.033-x) And thusx^2+0.011x-3.63xx10^-4=0 We get x=0.014*mol*L^-1 as the positive root And so AT EQUILIBIRUM [HOCl]=(0.033-0.014)*mol*L^-1=0.019*mol*L^-1 [""^(-)OCl]=0.014*mol*L^-1 [H_3O^+]=0.014*mol*L^-1=0.014*mol*L^-1 And it is typical for a weak acid at LOW concentrations, to dissociate more than it would normally would pH=-log_10(0.014)=1.85 1/2 Cl2 + H2O HClO + H+ + 2 e ⇌ Cl– + H2O ClO– + H2O + 2 e ⇌ Cl– + 2 OH– ClO2 + H+ + e ⇌ HClO2 HClO2 + 2 H+ + 2 e ⇌ HClO + H2O . Standard Redox Potential Table from Electrochemical Series by Petr VanýsekIn this video we will look at the equation for HClO2 + H2O and write the How to Write the Net Ionic Equation for HClO + NaOH = NaClO + H2O. In this video we will look at the equation for HClO2 + H2O and write the products. When we add HClO2 to H2O the HClO2 will dissociate and break into H+ an. In this video we will look at the equation for HClO2 + H2O and write the products. When we add HClO2 to H2O the HClO2 will dissociate and break into H+ an
Standard Redox Potential Table By ChinHsien Cheng - Issuu
Poisonous gas used in treatment of water: Cl2 (g) + H2O (l) <=> HClO (aq) + HCl (aq) -> HClO kills bacteria. Click again to see term. Tap again to see term.Which one of the following pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched? Acid Conjugate Base a. HF F- b. HClO ClO- c. H2O OH [HClO] rate=k.[OH^-]. HClO2 is a weak acid and HClO is even weaker. Water H2O OH-1.0 x 10-14 14.0 Group I metal hydroxides
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HClO2 +H2O (Chlorous Acid + Water) - YouTube
HClO (aq) + H2O (l) <-> ClO- (aq) + H3O (aq) of the following statements correctly describe a saturated solution of a slightly soluble ionic compound in H2O?HClO(aq)+H2O(l)--->H3O+(aq)+ClO-(aq) Check All That Apply HClO/H2O H3O+/ClO- H3O+/H2O HClO/ClO-. This problem has been solved! See the answer.Equation and oxidation of the reaction between chlorine and water. Cl2(g) + H20 (l) <==> HClO (aq) + HCL (aq) Chlorine's oxidation state on left = 0. Chlorine's Is there any reason why not to use Hypochlorous Acid (HClO) and Hydrogen Peroxide (H2O2) together in water (H2O). Share. Share a link to this question.
We deal with the equation...
#HOCl(aq) +H_2O(l)rightleftharpoonsH_3O^+ +""^(-)OCl#..
...the place #K_a=0.011=([H_3O^+][""^(-)OCl])/([HOCl])#
And if #x*mol*L^-1# dissociates...
#0.011=x^2/(0.033-x)#
And so #x^2=0.011xx(0.033-x)#
And thus...#x^2+0.011x-3.63xx10^-4=0#
We get #x=0.014*mol*L^-1# as the positive root...
And so AT EQUILIBIRUM...
#[HOCl]=(0.033-0.014)*mol*L^-1=0.019*mol*L^-1#
#[""^(-)OCl]=0.014*mol*L^-1#
#[H_3O^+]=0.014*mol*L^-1=0.014*mol*L^-1#
And it's typical for a susceptible acid at LOW concentrations, to dissociate more than it might usually would...
#pH=-log_10(0.014)=1.85#
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